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bootm: Reduce the unnecessary memmove

Although load address and image start address are same address,
bootm command always does memmove.
That is unnecessary memmove and can be taken few milliseconds
(about 500 msec to 1000 msec).
If skip this memmove, we can reduce the boot time.

Signed-off-by: Minkyu Kang <mk7.kang@samsung.com>
Minkyu Kang 16 년 전
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1개의 변경된 파일4개의 추가작업 그리고 2개의 파일을 삭제
  1. 4 2
      common/cmd_bootm.c

+ 4 - 2
common/cmd_bootm.c

@@ -340,8 +340,10 @@ static int bootm_load_os(image_info_t os, ulong *load_end, int boot_progress)
 		} else {
 			printf ("   Loading %s ... ", type_name);
 
-			memmove_wd ((void *)load,
-				   (void *)image_start, image_len, CHUNKSZ);
+			if (load != image_start) {
+				memmove_wd ((void *)load,
+						(void *)image_start, image_len, CHUNKSZ);
+			}
 		}
 		*load_end = load + image_len;
 		puts("OK\n");