Browse Source

lib_generic memcpy: copy one word at a time if possible

If source and destination are aligned, this copies ulong values
until possible, trailing part is copied by byte. Thanks for the details
to Wolfgang Denk, Mike Frysinger, Peter Tyser, Chris Moore.

Signed-off-by: Alessandro Rubini <rubini@unipv.it>
Acked-by: Andrea Gallo <andrea.gallo@stericsson.com>
Acked-by: Mike Frysinger <vapier@gentoo.org>
Alessandro Rubini 15 năm trước cách đây
mục cha
commit
ecd830b863
1 tập tin đã thay đổi với 15 bổ sung4 xóa
  1. 15 4
      lib_generic/string.c

+ 15 - 4
lib_generic/string.c

@@ -446,12 +446,23 @@ char * bcopy(const char * src, char * dest, int count)
  * You should not use this function to access IO space, use memcpy_toio()
  * or memcpy_fromio() instead.
  */
-void * memcpy(void * dest,const void *src,size_t count)
+void * memcpy(void *dest, const void *src, size_t count)
 {
-	char *tmp = (char *) dest, *s = (char *) src;
-
+	unsigned long *dl = (unsigned long *)dest, *sl = (unsigned long *)src;
+	char *d8, *s8;
+
+	/* while all data is aligned (common case), copy a word at a time */
+	if ( (((ulong)dest | (ulong)src) & (sizeof(*dl) - 1)) == 0) {
+		while (count >= sizeof(*dl)) {
+			*dl++ = *sl++;
+			count -= sizeof(*dl);
+		}
+	}
+	/* copy the reset one byte at a time */
+	d8 = (char *)dl;
+	s8 = (char *)sl;
 	while (count--)
-		*tmp++ = *s++;
+		*d8++ = *s8++;
 
 	return dest;
 }