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pi-futex: set PF_EXITING without taking ->pi_lock

It is a bit annoying that do_exit() takes ->pi_lock to set PF_EXITING.  All
we need is to synchronize with lookup_pi_state() which saw this task
without PF_EXITING under ->pi_lock.

Change do_exit() to use spin_unlock_wait().

Signed-off-by: Oleg Nesterov <oleg@tv-sign.ru>
Acked-by: Ingo Molnar <mingo@elte.hu>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
Oleg Nesterov %!s(int64=17) %!d(string=hai) anos
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Modificáronse 1 ficheiros con 3 adicións e 3 borrados
  1. 3 3
      kernel/exit.c

+ 3 - 3
kernel/exit.c

@@ -931,13 +931,13 @@ fastcall NORET_TYPE void do_exit(long code)
 		schedule();
 		schedule();
 	}
 	}
 
 
+	tsk->flags |= PF_EXITING;
 	/*
 	/*
 	 * tsk->flags are checked in the futex code to protect against
 	 * tsk->flags are checked in the futex code to protect against
 	 * an exiting task cleaning up the robust pi futexes.
 	 * an exiting task cleaning up the robust pi futexes.
 	 */
 	 */
-	spin_lock_irq(&tsk->pi_lock);
-	tsk->flags |= PF_EXITING;
-	spin_unlock_irq(&tsk->pi_lock);
+	smp_mb();
+	spin_unlock_wait(&tsk->pi_lock);
 
 
 	if (unlikely(in_atomic()))
 	if (unlikely(in_atomic()))
 		printk(KERN_INFO "note: %s[%d] exited with preempt_count %d\n",
 		printk(KERN_INFO "note: %s[%d] exited with preempt_count %d\n",