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PCI: remove redundant checking in PCI Express capability routines

There are a number of redundant pci_is_pcie() checks in various PCI
Express capabilities related routines like the following:

    if (!pci_is_pcie(dev))
	return false;

    pos = pci_pcie_cap(dev);
    if (!pos)
	return false;

The current pci_is_pcie() implementation is merely:

    static inline bool pci_is_pcie(struct pci_dev *dev)
    {
        return !!pci_pcie_cap(dev);
    }

so we can just drop the pci_is_pcie() test in such cases.

Acked-by: Donald Dutile <ddutile@redhat.com>
Signed-off-by: Myron Stowe <myron.stowe@redhat.com>
Signed-off-by: Bjorn Helgaas <bhelgaas@google.com>
Myron Stowe 13 жил өмнө
parent
commit
cb97ae3485
1 өөрчлөгдсөн 1 нэмэгдсэн , 13 устгасан
  1. 1 13
      drivers/pci/pci.c

+ 1 - 13
drivers/pci/pci.c

@@ -1994,7 +1994,7 @@ void pci_enable_ari(struct pci_dev *dev)
 		return;
 
 	bridge = dev->bus->self;
-	if (!bridge || !pci_is_pcie(bridge))
+	if (!bridge)
 		return;
 
 	pos = pci_pcie_cap(bridge);
@@ -2054,9 +2054,6 @@ void pci_disable_ido(struct pci_dev *dev, unsigned long type)
 	int pos;
 	u16 ctrl;
 
-	if (!pci_is_pcie(dev))
-		return;
-
 	pos = pci_pcie_cap(dev);
 	if (!pos)
 		return;
@@ -2096,9 +2093,6 @@ int pci_enable_obff(struct pci_dev *dev, enum pci_obff_signal_type type)
 	u16 ctrl;
 	int ret;
 
-	if (!pci_is_pcie(dev))
-		return -ENOTSUPP;
-
 	pos = pci_pcie_cap(dev);
 	if (!pos)
 		return -ENOTSUPP;
@@ -2149,9 +2143,6 @@ void pci_disable_obff(struct pci_dev *dev)
 	int pos;
 	u16 ctrl;
 
-	if (!pci_is_pcie(dev))
-		return;
-
 	pos = pci_pcie_cap(dev);
 	if (!pos)
 		return;
@@ -2174,9 +2165,6 @@ static bool pci_ltr_supported(struct pci_dev *dev)
 	int pos;
 	u32 cap;
 
-	if (!pci_is_pcie(dev))
-		return false;
-
 	pos = pci_pcie_cap(dev);
 	if (!pos)
 		return false;