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x86/32: Print control and debug registers for kerenel context

While for a user mode register dump it may be reasonable to skip
those (albeit x86-64 doesn't do so), for kernel mode dumps these
should be printed to make sure all information possibly
necessary for analysis is available.

Signed-off-by: Jan Beulich <jbeulich@suse.com>
Link: http://lkml.kernel.org/r/4F58889202000078000770E7@nat28.tlf.novell.com
Signed-off-by: Ingo Molnar <mingo@elte.hu>
Jan Beulich 13 年之前
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共有 1 个文件被更改,包括 1 次插入1 次删除
  1. 1 1
      arch/x86/kernel/dumpstack_32.c

+ 1 - 1
arch/x86/kernel/dumpstack_32.c

@@ -87,7 +87,7 @@ void show_registers(struct pt_regs *regs)
 	int i;
 
 	print_modules();
-	__show_regs(regs, 0);
+	__show_regs(regs, !user_mode_vm(regs));
 
 	printk(KERN_EMERG "Process %.*s (pid: %d, ti=%p task=%p task.ti=%p)\n",
 		TASK_COMM_LEN, current->comm, task_pid_nr(current),