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sched: Remove SYNC_WAKEUPS feature

Sync wakeups are critical functionality with a long history.  Remove it, we don't
need the branch or icache footprint.

Signed-off-by: Mike Galbraith <efault@gmx.de>
Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl>
LKML-Reference: <1268301817.6785.47.camel@marge.simson.net>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
Mike Galbraith 15 vuotta sitten
vanhempi
commit
c6ee36c423
2 muutettua tiedostoa jossa 0 lisäystä ja 11 poistoa
  1. 0 3
      kernel/sched.c
  2. 0 8
      kernel/sched_features.h

+ 0 - 3
kernel/sched.c

@@ -2369,9 +2369,6 @@ static int try_to_wake_up(struct task_struct *p, unsigned int state,
 	unsigned long flags;
 	struct rq *rq;
 
-	if (!sched_feat(SYNC_WAKEUPS))
-		wake_flags &= ~WF_SYNC;
-
 	this_cpu = get_cpu();
 
 	smp_wmb();

+ 0 - 8
kernel/sched_features.h

@@ -22,14 +22,6 @@ SCHED_FEAT(WAKEUP_PREEMPT, 1)
  */
 SCHED_FEAT(ASYM_GRAN, 1)
 
-/*
- * Use the SYNC wakeup hint, pipes and the likes use this to indicate
- * the remote end is likely to consume the data we just wrote, and
- * therefore has cache benefit from being placed on the same cpu, see
- * also AFFINE_WAKEUPS.
- */
-SCHED_FEAT(SYNC_WAKEUPS, 1)
-
 /*
  * Based on load and program behaviour, see if it makes sense to place
  * a newly woken task on the same cpu as the task that woke it --