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x86: fix nodemap_size according to nodeid bits

memnode.map is s16 array because of nodeid is 16 bit now.

so need to increase the nodemap_size according to that bits.

Signed-off-by: Yinghai Lu <yinghai.lu@sun.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
Yinghai Lu há 17 anos atrás
pai
commit
afadcd788f
1 ficheiros alterados com 1 adições e 1 exclusões
  1. 1 1
      arch/x86/mm/numa_64.c

+ 1 - 1
arch/x86/mm/numa_64.c

@@ -92,7 +92,7 @@ static int __init allocate_cachealigned_memnodemap(void)
 
 	pad = L1_CACHE_BYTES - 1;
 	pad_addr = 0x8000;
-	nodemap_size = pad + memnodemapsize;
+	nodemap_size = pad + sizeof(s16) * memnodemapsize;
 	nodemap_addr = find_e820_area(pad_addr, end_pfn<<PAGE_SHIFT,
 				      nodemap_size);
 	if (nodemap_addr == -1UL) {