Kaynağa Gözat

i386: no need to make enable_cpu_hotplug a variable

As long as there's no write access to this variable there's no reason to
let gcc check it at runtime.

[ tglx: arch/x86 adaptation ]

Signed-off-by: Adrian Bunk <bunk@stusta.de>
Signed-off-by: Andi Kleen <ak@suse.de>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
Adrian Bunk 17 yıl önce
ebeveyn
işleme
a850cef77f
2 değiştirilmiş dosya ile 3 ekleme ve 6 silme
  1. 3 3
      arch/x86/kernel/topology.c
  2. 0 3
      include/asm-x86/cpu.h

+ 3 - 3
arch/x86/kernel/topology.c

@@ -44,15 +44,15 @@ int arch_register_cpu(int num)
 	 * Also certain PCI quirks require not to enable hotplug control
 	 * for all CPU's.
 	 */
-	if (num && enable_cpu_hotplug)
+#ifdef CONFIG_HOTPLUG_CPU
+	if (num)
 		cpu_devices[num].cpu.hotpluggable = 1;
+#endif
 
 	return register_cpu(&cpu_devices[num].cpu, num);
 }
 
 #ifdef CONFIG_HOTPLUG_CPU
-int enable_cpu_hotplug = 1;
-
 void arch_unregister_cpu(int num) {
 	return unregister_cpu(&cpu_devices[num].cpu);
 }

+ 0 - 3
include/asm-x86/cpu.h

@@ -13,9 +13,6 @@ struct i386_cpu {
 extern int arch_register_cpu(int num);
 #ifdef CONFIG_HOTPLUG_CPU
 extern void arch_unregister_cpu(int);
-extern int enable_cpu_hotplug;
-#else
-#define enable_cpu_hotplug	0
 #endif
 
 DECLARE_PER_CPU(int, cpu_state);