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regulator: clear state each invocation of of_regulator_match

of_regulator_match() saves some dynamcially allocated state into the
match table that's passed to it. By implementation and not contract, for
each match table entry, if non-NULL state is already present,
of_regulator_match() will not overwrite it. of_regulator_match() is
typically called each time a regulator is probe()d. This means it is
called with the same match table over and over again if a regulator
triggers deferred probe. This results in stale, kfree()d data being left
in the match table from probe to probe, which causes a variety of crashes
or use of invalid data.

Explicitly free all output state from of_regulator_match() before
generating new results in order to avoid this.

Signed-off-by: Stephen Warren <swarren@nvidia.com>
Signed-off-by: Mark Brown <broonie@opensource.wolfsonmicro.com>
Cc: stable@vger.kernel.org
Stephen Warren 12 years ago
parent
commit
a2f95c3637
1 changed files with 6 additions and 0 deletions
  1. 6 0
      drivers/regulator/of_regulator.c

+ 6 - 0
drivers/regulator/of_regulator.c

@@ -120,6 +120,12 @@ int of_regulator_match(struct device *dev, struct device_node *node,
 	if (!dev || !node)
 		return -EINVAL;
 
+	for (i = 0; i < num_matches; i++) {
+		struct of_regulator_match *match = &matches[i];
+		match->init_data = NULL;
+		match->of_node = NULL;
+	}
+
 	for_each_child_of_node(node, child) {
 		name = of_get_property(child,
 					"regulator-compatible", NULL);