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@@ -231,26 +231,35 @@ void ath9k_cmn_rx_skb_postprocess(struct ath_common *common,
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{
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struct ath_hw *ah = common->ah;
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struct ieee80211_hdr *hdr;
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- int hdrlen, padsize;
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+ int hdrlen, padpos, padsize;
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u8 keyix;
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__le16 fc;
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/* see if any padding is done by the hw and remove it */
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hdr = (struct ieee80211_hdr *) skb->data;
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hdrlen = ieee80211_get_hdrlen_from_skb(skb);
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+ padpos = 24;
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fc = hdr->frame_control;
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+ if ((fc & cpu_to_le16(IEEE80211_FCTL_FROMDS|IEEE80211_FCTL_TODS)) ==
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+ cpu_to_le16(IEEE80211_FCTL_FROMDS|IEEE80211_FCTL_TODS)) {
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+ padpos += 6; /* ETH_ALEN */
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+ }
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+ if ((fc & cpu_to_le16(IEEE80211_STYPE_QOS_DATA|IEEE80211_FCTL_FTYPE)) ==
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+ cpu_to_le16(IEEE80211_STYPE_QOS_DATA|IEEE80211_FTYPE_DATA)) {
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+ padpos += 2;
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+ }
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/* The MAC header is padded to have 32-bit boundary if the
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* packet payload is non-zero. The general calculation for
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* padsize would take into account odd header lengths:
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- * padsize = (4 - hdrlen % 4) % 4; However, since only
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+ * padsize = (4 - padpos % 4) % 4; However, since only
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* even-length headers are used, padding can only be 0 or 2
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* bytes and we can optimize this a bit. In addition, we must
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* not try to remove padding from short control frames that do
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* not have payload. */
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- padsize = hdrlen & 3;
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- if (padsize && hdrlen >= 24) {
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- memmove(skb->data + padsize, skb->data, hdrlen);
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+ padsize = padpos & 3;
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+ if (padsize && skb->len>=padpos+padsize+FCS_LEN) {
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+ memmove(skb->data + padsize, skb->data, padpos);
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skb_pull(skb, padsize);
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}
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