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perf sched: Fix nsec to msec conversion

We are dividing a time in ns by 1e9. This is a nsec to sec
conversion. What we want is msecs. Fix it by dividing by 1e6.

Signed-off-by: Frederic Weisbecker <fweisbec@gmail.com>
Cc: Peter Zijlstra <a.p.zijlstra@chello.nl>
Cc: Mike Galbraith <efault@gmx.de>
Cc: Paul Mackerras <paulus@samba.org>
Cc: Arnaldo Carvalho de Melo <acme@redhat.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
Frederic Weisbecker há 15 anos atrás
pai
commit
7362262687
1 ficheiros alterados com 4 adições e 4 exclusões
  1. 4 4
      tools/perf/builtin-sched.c

+ 4 - 4
tools/perf/builtin-sched.c

@@ -1129,9 +1129,9 @@ static void output_lat_thread(struct task_atoms *atom_list)
 	avg = atom_list->total_lat / atom_list->nb_atoms;
 
 	printf("|%9.3f ms |%9llu | avg:%9.3f ms | max:%9.3f ms |\n",
-	      (double)atom_list->total_runtime / 1e9,
-		 atom_list->nb_atoms, (double)avg / 1e9,
-		 (double)atom_list->max_lat / 1e9);
+	      (double)atom_list->total_runtime / 1e6,
+		 atom_list->nb_atoms, (double)avg / 1e6,
+		 (double)atom_list->max_lat / 1e6);
 }
 
 static void __cmd_lat(void)
@@ -1157,7 +1157,7 @@ static void __cmd_lat(void)
 
 	printf("-----------------------------------------------------------------------------------\n");
 	printf(" TOTAL:            |%9.3f ms |%9Ld |\n",
-		(double)all_runtime/1e9, all_count);
+		(double)all_runtime/1e6, all_count);
 	printf("---------------------------------------------\n");
 }