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[PATCH] sched: optimize activate_task for RT task

RT task does not participate in interactiveness priority and thus shouldn't
be bothered with timestamp and p->sleep_type manipulation when task is
being put on run queue.  Bypass all of the them with a single if (rt_task)
test.

Signed-off-by: Ken Chen <kenneth.w.chen@intel.com>
Acked-by: Ingo Molnar <mingo@elte.hu>
Cc: Nick Piggin <nickpiggin@yahoo.com.au>
Cc: "Siddha, Suresh B" <suresh.b.siddha@intel.com>
Signed-off-by: Andrew Morton <akpm@osdl.org>
Signed-off-by: Linus Torvalds <torvalds@osdl.org>
Chen, Kenneth W 18 年之前
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共有 1 个文件被更改,包括 5 次插入3 次删除
  1. 5 3
      kernel/sched.c

+ 5 - 3
kernel/sched.c

@@ -940,6 +940,9 @@ static void activate_task(struct task_struct *p, struct rq *rq, int local)
 {
 {
 	unsigned long long now;
 	unsigned long long now;
 
 
+	if (rt_task(p))
+		goto out;
+
 	now = sched_clock();
 	now = sched_clock();
 #ifdef CONFIG_SMP
 #ifdef CONFIG_SMP
 	if (!local) {
 	if (!local) {
@@ -961,8 +964,7 @@ static void activate_task(struct task_struct *p, struct rq *rq, int local)
 				     (now - p->timestamp) >> 20);
 				     (now - p->timestamp) >> 20);
 	}
 	}
 
 
-	if (!rt_task(p))
-		p->prio = recalc_task_prio(p, now);
+	p->prio = recalc_task_prio(p, now);
 
 
 	/*
 	/*
 	 * This checks to make sure it's not an uninterruptible task
 	 * This checks to make sure it's not an uninterruptible task
@@ -987,7 +989,7 @@ static void activate_task(struct task_struct *p, struct rq *rq, int local)
 		}
 		}
 	}
 	}
 	p->timestamp = now;
 	p->timestamp = now;
-
+out:
 	__activate_task(p, rq);
 	__activate_task(p, rq);
 }
 }