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ppp: reuse print_hex_dump_bytes

There is a native function to dump hex buffers.

Signed-off-by: Andy Shevchenko <andriy.shevchenko@linux.intel.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
Andy Shevchenko 12 years ago
parent
commit
167bfa7184
1 changed files with 2 additions and 51 deletions
  1. 2 51
      drivers/net/ppp/ppp_synctty.c

+ 2 - 51
drivers/net/ppp/ppp_synctty.c

@@ -105,64 +105,15 @@ static const struct ppp_channel_ops sync_ops = {
 };
 
 /*
- * Utility procedures to print a buffer in hex/ascii
+ * Utility procedure to print a buffer in hex/ascii
  */
-static void
-ppp_print_hex (register __u8 * out, const __u8 * in, int count)
-{
-	register __u8 next_ch;
-	static const char hex[] = "0123456789ABCDEF";
-
-	while (count-- > 0) {
-		next_ch = *in++;
-		*out++ = hex[(next_ch >> 4) & 0x0F];
-		*out++ = hex[next_ch & 0x0F];
-		++out;
-	}
-}
-
-static void
-ppp_print_char (register __u8 * out, const __u8 * in, int count)
-{
-	register __u8 next_ch;
-
-	while (count-- > 0) {
-		next_ch = *in++;
-
-		if (next_ch < 0x20 || next_ch > 0x7e)
-			*out++ = '.';
-		else {
-			*out++ = next_ch;
-			if (next_ch == '%')   /* printk/syslogd has a bug !! */
-				*out++ = '%';
-		}
-	}
-	*out = '\0';
-}
-
 static void
 ppp_print_buffer (const char *name, const __u8 *buf, int count)
 {
-	__u8 line[44];
-
 	if (name != NULL)
 		printk(KERN_DEBUG "ppp_synctty: %s, count = %d\n", name, count);
 
-	while (count > 8) {
-		memset (line, 32, 44);
-		ppp_print_hex (line, buf, 8);
-		ppp_print_char (&line[8 * 3], buf, 8);
-		printk(KERN_DEBUG "%s\n", line);
-		count -= 8;
-		buf += 8;
-	}
-
-	if (count > 0) {
-		memset (line, 32, 44);
-		ppp_print_hex (line, buf, count);
-		ppp_print_char (&line[8 * 3], buf, count);
-		printk(KERN_DEBUG "%s\n", line);
-	}
+	print_hex_dump_bytes("", DUMP_PREFIX_NONE, buf, count);
 }